Assume two computers are using time division multiplexing to take turns in sending 512 byte packets

Assume two computers are using time division multiplexing to take turns in sending 512 byte packets over a shared channel that operates at 40000 bits per second. If the hardware takes 10msec after one computer stops sending before the other can begin, how long it will take for each of the computers

to send 1megabyte of a file?

Assume two computers are using time division multiplexing to take turns in sending 512 byte packets over a shamicrosoft office

Each computer will be sending 1024^2/512 = 2048 packets. Therefore:

Transfer time for each computer

= (1024^2 * 8 / 20000)s + 10ms * (2048-1)

= 419.4304 s + 0.01 * 2047

= 439.9 s